X^2-3x-40/x-8

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Solution for X^2-3x-40/x-8 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

X^2-(3*x)-(40/x)-8 = 0

X^2-3*x-40*x^-1-8 = 0

-3*x^1-40*x^-1-8*x^0 = 0

(-3*x^2-8*x^1-40*x^0)/(x^1) = 0 // * x^2

x^1*(-3*x^2-8*x^1-40*x^0) = 0

x^1

-3*x^2-8*x-40 = 0

-3*x^2-8*x-40 = 0

DELTA = (-8)^2-(-40*(-3)*4)

DELTA = -416

DELTA < 0

x in { } 

x belongs to the empty set

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